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The molar conductivity of 0.05 M BaCl(2)...

The molar conductivity of 0.05 M `BaCl_(2)` solution at `25^(@)C` is `223 Omega^(-1)"cm"^(2) mol^(-1)`. What is its conductivity?

Text Solution

Verified by Experts

Given : `C=0.05 M. Lambda = 223Omega^(-1)cm^(2)"mol"^(-1),k=?`
`Lambda=(1000k)/(C)`
`therefore" "k=(C xx Lambda)/(1000)`
`=(0.05xx223)/(1000)=(11.15)/(1000)`
`therefore" "k=0.01115"S cm"^(-1)`
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