हल करें `sec^(2)2x=1-tan2x`

Explanation

दिया गया समीकरण
`:. 1+tan^(2)2x=1-tan2x`
`rArr tan^(2)2x+tan 2x=0`
`rArr tan 2x(tan 2x+1)=0`
`rArr tan x=0 or tan 2x=-1`
अब `tan 2x=0 rArr 2x=npi`
`:. n=(npi)/(2),n in Z " "...(2)`
पुनः `tan2x=-1 rArr tan 2x= tan (-(pi)/(4))`
`:. 2x= pi-(pi)/(4) or x =(n pi)/(2)-(pi)/(8), n in Z`
अतः अभीष्ट हल है `x=(npi)/(2),(n pi)/(2)-(pi)/(8), n in Z`