(C) In the diagram, the parallelogram of the base BC of AABC PQ is drawn. If PQ: BC = 1: 3, then The ratio of AP and PB will be

Points P and Q lie on sides AB and AC of triangle ABC respectively such that segment PQ is parallel to side BC. If the ratio of areas of triangle APQ: triangle ABC is 25 : 36, then the ratio PA : PB is

P is a point on the side BC of DeltaABC and Q is a point such that PQ is the resultant of AP,PB and PC. Then, ABQC is a

A line PQ is drawn parallel to the base BC of Delta ABC which meets sides AB and AC at points P and Q respectively. If AP = 1/3 PB , find the value of : ("Area of " Delta ABC)/("Area of "Delta APQ)

In the figure bc || pq then find the value of xyz. 60

A line PQ drawn parallel to the base BC of ∆ABC intersects AB and AC at P and Q respectively. AP = 1/3 PB then determine (area of ABC)/(area of APQ)

P is a point on the side BC off the DeltaABC and Q is a point such that PQ is the resultant of AP,PB and PC. Then, ABQC is a

P is a point on the side BC off the DeltaABC and Q is a point such that PQ is the resultant of AP,PB and PC. Then, ABQC is a

P is a point on the side BC off the DeltaABC and Q is a point such that PQ is the resultant of AP,PB and PC. Then, ABQC is a

P is a point on the side BC off the DeltaABC and Q is a point such that PQ is the resultant of AP,PB and PC. Then, ABQC is a

In triangleABC , a straight line parallel to BC intersects AB and AC at P and Q respectively. If AB = 3PB, then PQ : BC =