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The correct Answer is:
RD SHARMA-त्रिकोणमितीय सर्वसमिकाएँ -बहु विकल्पीय प्रश्न
- (sin theta)/(1+cos theta)=
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- (sin theta)/(1-cot theta)+(cos theta)/(1-tan theta)=
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- (1+ cot theta - cosec theta) (1+ tan theta+ sec theta)=
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- (tan theta)/(sec theta-1)+(tan theta)/(sec theta+1)=
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- (cosec theta - sin theta) (sec theta -cos theta) (tan theta+cot theta)
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- यदि x=a cos theta तथा y=b sin theta हो, तो b^(2)x^(2)+a^(2)y^(2)=
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- यदि x=a sec theta तथा y=b tan theta हो, तो b^(2)x^(2)-a^(2)y^(2)=
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- (cot theta)/(cot theta - cot 3 theta)+(tan theta)/(tan theta- tan 3the...
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- 2(sin ^(6) theta+ cos ^(6)theta) -3(sin ^(4) theta+ cos ^(4)theta)=
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- यदि a cos theta+ b sin theta=4 तथा a sin theta-b cos theta =3 हो, तो ...
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- यदि a cot theta + b cosec theta=p तथा b cot theta +a cosec theta =q ह...
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- sin ^(2)29^(@) + sin ^(2) 61^(@) =
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- यदि x=r sin theta cos phi, y=r sin theta sin phi तथा z=r cos theta ह...
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- यदि sin theta+ sin ^(2) theta =1 हो, तो cos ^(2)theta+ cos ^(4) theta...
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- यदि a cos theta +b sin theta=m तथा a sin theta -b cos theta = n हो, ...
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- यदि cos A+ cos ^(2)A=1 हो, तो sin ^(2)A+ sin ^(4)A=
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- यदि x=a sec theta cos theta, y=b sec theta sin theta तथा z=c tan thet...
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- यदि a cos theta- b sin theta=c हो, तो a sin theta+ b cos theta=
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- 9 sec ^(2)A-9 tan ^(2) A=
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- (1+tan theta+sec theta)(1+cot theta-cosec theta)=
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