A small block of mass `m` is placed at rest on the top of a smooth wedge of mass M, which in turn is placed at rest on a smooth horizontal surface as shown in figure. It h be the height of wedge and `theta` is the inclination, then the distance moved by the wedge as the block reaches the foot of the wedge is

Options

A. `(Mhcottheta)/(M+m)`
B. (b) `(mhcottheta)/(M+m)`
C. (c) `(Mhcosectheta)/(M+m)`
D. (d) `(mhcosectheta)/(M+m)`

Answer

B

Explanation

Horizontal side of wedge is `h cottheta`.
(##DCP_V02_CH11_E01_098_S01.png" width="80%">
`Mx=m(hcot theta-x)`
`:." " x=(mhcottheta)/(M+m)`