using the illustration when both surfaces 1 and 2 are exposed to the atmoshere, `P_1` and `P_2` are gauge pressure , and `h_1` and `h_2` are heights .

The Bernoulli equation for this situation is `h_1+P_1 /W+V_1^2/"2a"=h_2+P_2/W+V_2^2/"2a"`
If an Identical outlet were placed at exactly the same point on the left side of the container, the velocity would be

Options

A. zero
B. computable
C. `2V_2`
D. none of the above

Answer

B

Explanation

The question is self - explanatory