x के सापेक्ष अवकलन कीजिए ।
`(cosx)/(logx),x gt0`

Explanation

माना `y=(cosx)/(logx)`
`(dy)/(dx)=(d)/(dx)((cosx)/(logx))`
`=(logx.(d)/(dx)cosx-cosx(d)/(dx)logx)/((logx)^(2))`
`=(-sinx logx-cosx.(1)/(x))/((logx)^(2))`
`=-((x sin x logx+cosx))/(x(logx)^(2))`