A cylinder containing cooking gas can withstand a pressure of `15 atm`. The pressure gauge of the cylinder indicates `12 atm` at `27^(@)C`. Due to a sudden fire in the building, the temperature starts rising. At what temperature will the cylinder explode?

Explanation

To find the temperature at which the cylinder will explode, we can use the relationship between pressure and temperature for a gas at constant volume, which is derived from the ideal gas law. The formula we will use is:

\[ \frac{P_1}{T_1} = \frac{P_2}{T_2} \]

where:
- \( P_1 \) is the initial pressure (12 atm),
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