एक `Delta ABC `में , यदि `2/_A = 4/_B = 12 /_C ` है, तो कोणों की गणना कीजिए ।

Explanation

माना कि `2/_A = 4/_B = 12/_C = x^(@)`
तब `/_A = (1)/(2) x^(@) ,/_B = (1)/(4)x^(@) ` तथा `/_ C = (1)/(12) x^(@)`
किन्तु `/_A + /_B + /_C = 180^(@)`
इसलिए , `(1)/(2) x^(@) + (1)/(4) x^(@) + (1)/(12)x^(@) = 180^(@)`
`implies ((6+3+1)/(12)) x^(@) = 180^(@) implies (10)/(12)x^(@) = 180^(@)`
`implies (x^(@))/(12) = 18^(@)`
`:. x = 216^(@)`
`:. /_A = (1)/(2) . 216^(@) = 108^(@), /_ B = (1)/(4) . 216^(@)= 54^(@)` तथा `/_C = (1)/(12) . 216^(@) = 18^(@)`
अतः `/_A = 108^(@) , /_B = 54^(@) ` तथा `/_C = 18^(@)`