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The activation energy for a reaction at ...

The activation energy for a reaction at temperature T K was found to be or `2.303 "RT J mol"^(-1)`. The ratio of the rate constant to Arrhenius factor is

A

0.01

B

0.1

C

0.02

D

0.001

Text Solution

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The correct Answer is:
B
log K=log `A -(E_(a))/(2.303RT)`
logK-log `A-(E_(a))/(2.303RT)`
log `((K)/(A))=(-2.303RT)/(2.303RT)=-1`
`(k)/(A)="antilog" (-1.0)=1xx10^(-1)=0.1`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-CHEMICAL KINETICS -Exercise 1
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