The rate constant of a reaction is given as
`k=2.1xx10^(10)e^(-2700//RT)`
It means that
`"log "k " vs "1//T` will be a straight line with intercept on `"log "k" axis"=log2.1xx10^(10).`
Number of effective collisions of temperature are `2.1xx10^(10)cm^(-3)s^(-1).`
Half-life of a reaction increases of temperature.
`"log"k" vs "1//T` will be a straight line with `slope=-(2700)/(2.303R).`
Which of the above statements are true? Choose the correct option.

Options

A. I and II
B. II and III
C. III and IV
D. I and IV

Answer

d

Explanation

`k=2.1xx10^(10)e^(-2700//RT)`
`" ""In " k="In "2.1xx10^(10)+"In "e^(-2700//RT)`
`"log "k="log "2.1xx10^(10)-(2700)/(2.303RT)`
`"log"k=-(2700)/(2.303RT)(1)/(T)+"log "2.1xx10^(10).`
On comparing it with straight line equation, y=mx+c, we get
`therefore" "m(slope)=-(2700)/(2.303R)`
and `C("intercept")="log "2.1xx10^(10)`