If `a` is the initial concentration then time required to decompose half of the substance for nth order is inversely proportional to:

Options

A. `a^(n-2)`
B. `a^(1-n)`
C. `a^(n-1)`
D. `a^(n)`

Answer

B

Explanation

`t_(1//2)prop(1)/(a)^(n-1)`
where, a=initial concentration and n= order of reaction
`therefore" "t_(1//2)prop(a)^(1-n)`