If a,b and c are three non-zero vectors such that no two of these are collinear. If the vector a+2b is collinear with c and b+3c is collinear with a(`lamda` being some non-zero scalar), then a+2b+6c is equal to

Options

A. `lambdaa(lambda ne 0,"a scalar")`
B. `lambdab(lambda ne 0,"a scalar")`
C. `lambdac(lambda ne 0,"a scalar")`
D. 0

Answer

C

Explanation

Since, a + 2b = kc
`therefore a+2b+6c=kc+6c`
`=(k+6)c=lambdac" "[because lambda=k+rne0]`