The correct representation of Nernst equation for half-cell ,reaction `Cu^(2+) (aq) + e^(-) to Cu^(+) (aq)` is

Options

A. `E_(cu^(+),cu^(2+))^(@) = E_(cu^(+),cu^(2+))^(@) - (0.0592)/(2) log .([Cu^(+)])/([Cu^(2+)])`
B. `E_(cu^(+),cu^(2+))^(@) = E_(cu^(+),cu^(2+))^(@) - (0.0592)/(1) log .([Cu^(+)])/([Cu^(2+)])`
C. `E_(cu^(+),cu^(2+))^(@) = E_(cu^(+),cu^(2+))^(@) - (0.0592)/(2) log .([Cu^(+)])/([Cu^(2+)])`
D. `E_(cu^(+),cu^(2+))^(@) = E_(cu^(+),cu^(2+))^(@) - (0.0592)/(1) log .([Cu^(+)])/([Cu^(2+)])`

Answer

B, D

Explanation

`E_("cell") = E_("cell")^(@) - (0.0591)/(x) "log" ([p])/([R])`
for the half-cell
`Cu^(2+) (aq) + e^(-) to Cu^(+) (aq)`
The correct Nernst's equation is
`E_(Cu^(+),Cu^(2+)) = E_(Cu^(+),Cu^(2+)), - (0.0591)/(1) "log" ([Cu^(+)])/([Cu^(2+)])`