Two containers having boiling water and ice are connected through a conducting metal rod. The whole ice melts in time T. now the rod is cut into two equal parts and both parts are connected in parallel between the containers the time required to melt the same amount of ice will be

Options

A. `T`
B. `(T)/(2)`
C. `(T)/(4)`
D. `2T`

Explanation

`triangleQ=(kA(100-0))/(L).T` ….(i)
in second case
`triangleQ'(kA(100-0))/(L//2).T'`
Since `triangleQ=triangleQ'`
`thereforeT=4T'`
`T'=(T)/(4)`