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If 1,omega,omega^(2) are the cube roots...

If `1,omega,omega^(2)` are the cube roots of unity, then the roots of the equation `(x-1)^(3)+8=0` are

A

`-1,1+2omega,1+2omega^(2)`

B

`-1,1-2omega,1-2omega^(2)`

C

`-1-1-1`

D

None of these

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The correct Answer is:
B
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