How many `g`-atom of `S` are present in `196 g` of `H_(2)SO_(4)?`

Explanation

To find out how many gram-atoms of sulfur (S) are present in 196 g of sulfuric acid (H₂SO₄), we can follow these steps:

### Step 1: Determine the molar mass of H₂SO₄
The molar mass of H₂SO₄ can be calculated by adding the atomic masses of all the elements in the compound:
- Hydrogen (H): 1 g/mol × 2 = 2 g/mol
- Sulfur (S): 32 g/mol × 1 = 32 g/mol
- Oxygen (O): 16 g/mol × 4 = 64 g/mol

So, the total molar mass of H₂SO₄ is:
\[ \text{Molar mass of H₂SO₄} = 2 + 32 + 64 = 98 \text{ g/mol} \]

### Step 2: Calculate the number of moles of H₂SO₄ in 196 g
Using the formula:
\[ \text{Number of moles} = \frac{\text{mass}}{\text{molar mass}} \]
We can calculate the number of moles of H₂SO₄ in 196 g:
\[ \text{Number of moles of H₂SO₄} = \frac{196 \text{ g}}{98 \text{ g/mol}} = 2 \text{ moles} \]

### Step 3: Determine the number of moles of sulfur in H₂SO₄
Since there is 1 atom of sulfur in each molecule of H₂SO₄, the number of moles of sulfur is equal to the number of moles of H₂SO₄:
\[ \text{Number of moles of S} = 2 \text{ moles} \]

### Step 4: Convert moles of sulfur to gram-atoms
In chemistry, the term "gram-atom" is equivalent to the number of moles. Therefore, the number of gram-atoms of sulfur in 196 g of H₂SO₄ is:
\[ \text{Gram-atoms of S} = 2 \text{ gram-atoms} \]

### Final Answer:
There are **2 gram-atoms of sulfur (S)** present in 196 g of H₂SO₄.

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