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For the indicator the ratio ([Ind^(Theta...

For the indicator the ratio `([Ind^(Theta)])/(["Hin"])` is `7.0 "at" pH "of" 4.3. K_(aq)` for the indicator is

A

`3.5xx10^(-4)`

B

`3.5 xx 10^(-5)`

C

`3.5 xx10^(-2)`

D

`3.5 xx 10^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`PH=pK_("In")+"log"('[I_(n)^(-)])/(["Hin"])`
`4.3 =pk_("In")+log 7`
` 3.45 = pK_("In")`
`K_("In")=3.5xx10^(-4)`
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