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A certain reaction is at equilbrium at 8...

A certain reaction is at equilbrium at `82^(@)C and Delta H` for this reaction is 21.3 kJ. What would be the value of `Delta S` (in `JK^(-1)mol^(1)`) for the reaction?

A

`55.0 `

B

`60.0 `

C

`68.5`

D

`120.0`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaG= Delta H-T. Delta S`
At equlibarium
`Delta G=0`
`(DeltaH)/(T)=DeltaS`
`(21300)/(355) =Delta S`
`60=DeltaS`
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