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A solenoid coil of 300 turns//m is carry...

A solenoid coil of `300 turns//m` is carrying a current of `5A`. The length of the solenoid is `0*5m` and has a radius of `1cm`. Find the magnitude of the magnetic field well inside the solenoid.

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AI Generated Solution

To find the magnitude of the magnetic field inside a solenoid, we can use the formula: \[ B = \mu_0 n I \] where: - \( B \) is the magnetic field inside the solenoid, ...
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