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Given mass of the moon is 1/81 of the ma...

Given mass of the moon is 1/81 of the mass of the earth and corresponding radius is 1/4 of the earth. If escape velocity on the earth surface is 11.2 km / s , the value of same on the surface of the moon is

A

`1.25km//s`

B

`2.5m//s`

C

`5m//s`

D

`10m//s`

Text Solution

Verified by Experts

The correct Answer is:
B
`v_(e)=sqrt((2GM)/(R )),v_("e(moon)")=sqrt((2GM xx 4)/(81xx R))`
`= sqrt((4)/(81)((2GM)/(R )))=(2)/(9)xx v_(e )=2.5 m//s`
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MARVEL PUBLICATION-GRAVITATION -TEST YOUR GRASP -2
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