A student peddles a stationary bicycle. The pedals are connected to a coil of 100 turns and area `0.1 m^(-2)`. The coil is placed in a uniform magnetic field of `10^(-2) T`, perpendicular to the axis of rotation of the coil. What is the maximum voltage generated in the coil if the coil rotates at 60 revolution per minute?

Options

A. 3.14 V
B. 0.314 V
C. 0.628 V
D. 6.28 V

Answer

C

Explanation

`N = 1000, A=10^(-1) m^(2), f=1 rev//s =1 Hz`
`:. Omega = 2 pi f and B = 10^(-2)T`
The maximum voltage generated in the coil is
`E_(0) = NAB omega = NAB cdot (2 pi f)`
`=100 xx 10^(-1) xx 10^(-2) xx 2 xx 3.14 xx 1`
`=0.628V`.