A parallel plate capacitor having plate area `0.5 m^(2)` and plate separation of 5 mm is complete filled with a dielectric of dielectric constant 10. What is the instantaneous displacement current, if it is being charged at the rate of `100 V//s`? `[epsilon_(0)=8.85 xx 10^(-12)C^(2)N//m^(2)]`

Options

A. `8.85 mu A`
B. `0.885 mu A`
C. `0.177 mu A`
D. `1.77 mu A`

Answer

B

Explanation

The capacity of the parallel plate capacitor is given by
`C = (Kaepsilon_0)/d = (10 xx 5 xx 10^(-1) xx 8.85 xx 10^(-12))/(5 xx 10^(-3))`
`=8.85 xx 10^(-9) F`
`:.` Displacement current `I_(d) = C(dV)/(dt)`
`=8.85 xx 10^(-9) xx 100`
`=8.85 xx 10^(-7)A`
`=0.885 xx 10^(-6) A`
`:. I_(d) = 0.88r muA`.