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The transfer ration of a transistor is ...

The transfer ration of a transistor is `50`. The input resistance of the transistor when used in the common -emitter configuration is `1 kOmega`. The peak value for an `A.C.` input voltage of `0.01 V` peak is

A

250 `mum`

B

500 `mum`

C

750 `mum`

D

900 `mum`

Text Solution

Verified by Experts

The correct Answer is:
B
`I_b=V_i/R_i = 0.01/1000 = 0.01 xx 10^(-3) A` = 0.01 mA
`therefore I_c=betaI_b = 50xx0.01` = 0.5 mA = `500 muA`
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