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We can represent the decomposition of N(...

We can represent the decomposition of `N_(2)O_(5)(g)` at a fixed temperature by the following two chemical equations:
(P) `2N_(2)O_(5)(g) rarr 4NO_(2)(g)+O_(2)(g)`,
Activation energy `E_(a)`
(Q) `N_(2)O_(5)(g) rarr 2NO_(2)(g) +(1)/(2)O_(2)(g)`,
Activation energy `E'_(a)` then:

A

`E_(1)gtE_(2)`

B

`E_(1)lt E_(2) `

C

`E_(1)=2E_(2)`

D

`E_(1)=E_(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Energy of activation does not depend on number of molecules .
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For the first order reaction 2N_(2)O_(5)(g) rarr 4NO_(2)(g) + O_(2)(g)

For the decomposition of N_(2)O_(5)((g)) , it is given that: 2N_(2)O_(5g)rarr 4NO_(2(g))+O_(2(g)) , Activation energy E'_(a) then , E_(a), N_(2)O_(5(g))rarr 2NO_(2(g))+1//2O_(2(g)) , Activation energy E_(a)^(') then:

For a reaction, 2N_(2)O_(5)(g) to 4NO_(2)(g) + O_(2)(g) rate of reaction is:

The molecularity of a complex reaction given below is : 2N_(2)O_(5)(g)to4NO_(2)(g)+O_(2)(g)

For the reaction 2N_(2) O_(5) (g) overset(k)rarr 4NO_(2) (g) + O_(2) (g) having rate law. Rate = k [N_(2)O_(5)]=R_(1) Select correct statement.

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