A cyclist on the ground goes round a ciruclar path of circumference 34.3 m in `sqrt(22)` second. The angle made by him, with the vertical, will be:-

Options

A. `42^(@)`
B. `43^(@)`
C. `44^(@)`
D. `45^(@)`

Answer

D

Explanation

`tan theta=(v^(2))/(rg),V=(s)/(t)=(34.3)/(sqrt(22)),2 pi r =s`
`r=(s)/(2pi) `
`therefore tan theta =(34.3xx34.3)/(22xx(34.3)/(2xx22)xx7)`
`tan theta=1`
`theta = 45^(@)`