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A particle executes SHM with a time peri...

A particle executes SHM with a time period of 8 s. It is starts from the extreme position at time t = 0, the ratio of distances covered by it in 1st and 2nd seconds is

A

1

B

`1//(sqrt(2)-1)`

C

`1//(sqrt(3)-1)`

D

`sqrt(2)-1`

Text Solution

Verified by Experts

The correct Answer is:
B
`(A-y_(1))/(y_(1))=sqrt(2)-1 therefore (y_(1))/(A-y)=(1)/(sqrt(2)-1)`
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