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The displacement of a particle making S.H.M. is given by `x=6cos(100t+(pi)/(4))m` then the frequency is

A

`1.592 Hz`

B

`15.92 Hz`

C

`159.2 Hz`

D

`1592 Hz`

Text Solution

Verified by Experts

The correct Answer is:
B
`x=6cos(100t+(pi)/(4))`
`omega=100`
`2pin=100`
`n=(100)/(2pi)=(50)/(pi)=15.92Hz`.
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