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Two SHM's are represented by y = a sin (...

Two `SHM's` are represented by `y = a sin (omegat - kx)` and `y = b cos (omegat - kx)`. The phase difference between the two is :

A

`pi//2`

B

`pi//4`

C

`pi//6`

D

`3pi//4`

Text Solution

Verified by Experts

The correct Answer is:
A
`x_(1)=Asin(omegat-kx)`
`x_(2)=Bsin(omegat-kx+(pi)/(2))`
`deltaphi=(pi)/(2)` rad.
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