Two light waves of amplitudes `A_(1)` and `A_(2)` superimpose with each other such that `A_(1) gt A_(2)`. The difference between maximum and minimum amplitudes is

Options

A. `A_(1)+A_(2)`
B. `A_(1)-A_(2)`
C. `2A_(1)`
D. `2A_(2)`

Answer

D

Explanation

`R_("max")=A_(1)+A_(2)`
`R_(min)=A-A_(2)`
Difference at `R_(max) and R_(min)` is,
`R_(max)-R_(min)=A+A_(2)-A_(1)+A_(2)=2A_(2)`