In a region `10^(19) prop`-particles and `10^(19)` protons move to the left, while `10^(19)` electrons moves to the right per second. The current is

Options

A. 3.2 A towards left
B. 6.4 A towards left
C. 9.6 A towards left
D. 6.4 A towards right

Answer

B

Explanation

Electric current due to flow of `10^(19) alpha-`particles towards left is ,
`I_(1)=2 n_(1)e=2xx10^(19)xxe`
Electric current due to flow of `10^(19)` electrons towards left is ,
`I_(2)=10^(19)xxe`
Electric current due to flow of `10^(19)` protons towards left is ,
`I_(3)=10^(19)xxe`
Thus, total electric current is ,
`I=I_(1)+I_(2)+I_(3)=4e xx 10^(19)`
`=4xx1.6 xx 10^(-19)xx10^(19)=6.4` A