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The internal resistance of a cell by pot...

The internal resistance of a cell by potentiometer is given by

A

`r_(1)=R_(1)((l_(1)-l_(2))/(l_(2)))`

B

`r_(1)=R_(1)((E_(1)-V_(1))/(V_(1)))`

C

both 'a' and 'b'

D

neither 'a' nor 'b'

Text Solution

Verified by Experts

The correct Answer is:
C
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Internal resistance of a cell depends on

NIKITA PUBLICATION-CURRENT ELECTRICITY-Multiple Choice Questions
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  2. Potentiometer is used to

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  3. The internal resistance of a cell by potentiometer is given by

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  4. In potentiometer experiment to determine internal resistance of the ce...

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  5. The current, in a potentiometer wire of 100 cm length, is adjusted to ...

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  6. In given figure, the potentiometer wire AB has a resistance of 5 Omeg...

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  7. The wire of potentiometer has resistance 4 Omega and length 1m. It i...

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  8. A potentiometer has a uniform wire of length 10m and resistance 5 Ome...

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  9. A voltmeter has a resistance of 50 Omega is connected across a cell ...

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  10. With a potentiometer null point were obtained at 140 cm and 180 cm w...

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  11. In a potentiometer experiment it is found that no current passes throu...

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  12. The potential gradient along the length of a uniform wire is 5 V/m. Th...

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  13. In figure AB is a potentiometer wire of length 10 m and resistance 1...

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  14. In figure, AB is a potentiometer wire, length 10 m and resistance 2 Om...

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  15. A plantinum wire has resistance of 10 Omega at 0^(@)C and 20 Omega at ...

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  16. In the adjacent circuit the ammeter reads 5.0 A and voltmeter reads 20...

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  17. Following are the readings of potential and current through a specimen...

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  18. In a potentiometer experiment the balancing length is 8 m, when the tw...

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  19. Six cells each of e.m.f. 2 V and internal resistance 0.1Omega are conn...

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  20. Find the equivalent resistance of the network given in the figure,

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