Home
Class 12
PHYSICS
A proton, a deutron and an alpha particl...

A proton, a deutron and an alpha particle, after being accelerated through the same potential difference enter a region of uniform magnetic field `vecB`, in a direction perpendicular to `vecB`. Find the ratio of their kinetic energies. If the radius of proton's circular path is `7cm`, what will be the radii of the paths of deutron and alpha particle?

A

`2:1:1`

B

`2:2:1`

C

`1:2:1`

D

`2:1:2`

Text Solution

Verified by Experts

The correct Answer is:
D
`E=(q^2B^2r^2)/(2m)`
`therefore E prop (q^2)/(m)`
`E_P:E_d:E_alpha:(q_(p)^(2))/(m_p):(q_(d)^(2))/(m_d):(q_(alpha)^(2))/(m_alpha)`
`=(q_(p)^(2))/(m_p):(q_(p)^(2))/(2m_p):(4q_(p)^(2))/(4m_p)`
`=2:1:2`.
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF ELECTRIC CURRENT

    NIKITA PUBLICATION|Exercise MCQs (Sensitivity and accuracy of M.C.G.)|1 Videos

  • KINETIC THEORY OF GASES & RADIATION

    NIKITA PUBLICATION|Exercise MCQs (Question Given in MHT-CET)|79 Videos

  • MAGNETISM

    NIKITA PUBLICATION|Exercise MCQs|249 Videos

Similar Questions

Explore conceptually related problems

A proton, a deuteron and an alpha particle are accelerated through same potential difference and then they enter a normal uniform magnetic field, the ratio of their kinetic energies will be

A proton and an alpha -particle, accelerated through same potential difference, enter a region of uniform magnetic field with their velocities perpendicular to the field. Compare the radii of circular paths followed by them.

A proton and an alpha -particle are accelerated through same potential difference. Find the ratio of their de-Brogile wavelength.

A proton, a deuteron and an alpha particle, are accelerated through the same potential difference and then subjected to a unifrom magnetic field vecB , perpendicular to the direction of their motions. Compare (i) their kinetic energies, and (ii) if the radius of the ciruclar path described by proton is 5 cm, determine the radii of the paths described by deuteron and alpha partcile.

A proton and an alpha particle accelerated through the same potential difference enter a region of uniform magnetic field normally if the radius of the proton orbit is 10 cm ten radius of alpha particle is

If a proton, deuteron, and alpha particle on being accelerated by the same potential difference enters perpendicular to the magnetic field, then the ratio of their kinetic energies is

A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha -particle is