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A rectangular coil of 100 turns each of ...

A rectangular coil of 100 turns each of area `10 cm^2` hangs freely in radial magnetic field. The coil deflects through an angle of `30^@` when current of 0.5 m A is paased through it . If torsional constant of suspension fibre is `2.5 xx10^-9` Nm/rad, then magnetic field will be ,

A

`3.6xx10^-5Wb//m^2`

B

`2.2xx10^-5Wb//m^2`

C

`2.6xx10^-5Wb//m^2`

D

`4.2xx10^-5Wb//m^2`

Text Solution

Verified by Experts

The correct Answer is:
C

`B=(K theta )/(n AI)=(2.5xx10^-9xx5)/(10^2xx10^-3xx5xx6xx10^-4)`
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