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Two particles of masses ma and mb and sa...

Two particles of masses `m_a` and `m_b` and same charge are projected in a perpendicular magnetic field . They travel along circular paths of radius `r_(a)` and `r_(b)` such that `r_(a) gt r_(b)` . Then which is true ?

A

`m_av_agtm_bv_b`

B

`m_am_bandv_av_b`

C

`m_a=m_b and v_agtv_b`

D

`m_b=v_bgt m_agtv_a`

Text Solution

Verified by Experts

The correct Answer is:
A

`r=(mv)/(q B)`
According to given equation
`r_a gt r_b`
`(m_a v_a)/(q B)gt (m_b v_b)/(q B)`
i.e., `m_a v_a gt m_b v_b`.
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