Two particles of masses `m_a` and `m_b` and same charge are projected in a perpendicular magnetic field . They travel along circular paths of radius `r_(a)` and `r_(b)` such that `r_(a) gt r_(b)` . Then which is true ?
A
`m_av_agtm_bv_b`
B
`m_am_bandv_av_b`
C
`m_a=m_b and v_agtv_b`
D
`m_b=v_bgt m_agtv_a`
Text Solution
Verified by Experts
The correct Answer is:
A
`r=(mv)/(q B)` According to given equation `r_a gt r_b` `(m_a v_a)/(q B)gt (m_b v_b)/(q B)` i.e., `m_a v_a gt m_b v_b`.
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