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800 ml of 0.1 MH(2) SO(4) is mixed with ...

800 ml of 0.1 `MH_(2) SO_(4)` is mixed with 200ml of 0.8 `MH_(2) SO_(4)` The molarity of the mixture is

A

0.32

B

0.24

C

0.12

D

0.48

Text Solution

Verified by Experts

The correct Answer is:
B
`M_("mix")=(M_(1) V_(1) + M_(2) V_(2))/(V_(1) + V_(2))`
`((0.1 xx 0.8)+(0.2 xx 0.8))/(0.8 + 0.2)= 0.24 M `
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