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The mole of fraction of nitrogen, in a m...

The mole of fraction of nitrogen, in a mixture of 7 g of `N_(2)` and 16 g of `O_(2)` is

A

0.5

B

0.75

C

0.66

D

0.33

Text Solution

Verified by Experts

The correct Answer is:
D
Moles of `N_(2) = 7/28=0.25` and
Moles of `O_(2) = 16/32 = 0.5`
Mole fraction of `N_(2) = 0.25/(0.25 + 0.5)=0.33`
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