The osmotic pressure of solution containing `34.2 g` of cane sugar (molar mass = 342 g `mol^(-1)` ) in 1 L of solution at `20^(@)C` is (Given `R = 0.082` L atm `K^(-1) mol^(-1)` )

Options

A. 2.40 atm
B. 3.6 atm
C. 24 atm
D. 0.0024 atm

Answer

A

Explanation

Data:
`W_(2) = 34.2 g, M_(2) = 342 gmol^(-1),V=1 L`
`T = 20 xx 273 = 293 K` and `R=0.082 L atm K^(-1), pi=?`
Calculation:
To calculate `pi`
`pi= n_(2)RT`
`pi = W_(2)/M_(2) xx (RT)/V`
`=(34.2 g xx 0.082 L. atm K^(-1) mol^(-1) xx 293 K)/(342 g mol^(-1) xx 1L)`
`=(34.2 xx 82 xx 293 xx 10^(-3))/(342)` atm
`pi = 2.40` atm