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Arrange the following alkyl halides in d...

Arrange the following alkyl halides in decreasing order of the rate of `beta`-elimination reaction with alcoholic KOH.
(I) `CH_(3)-underset(CH_(3))underset(|)overset(H)overset(|)(C)-CH_(3)Br`
(II) `CH_(3)-CH_(2)-Br`
(III) `CH_(3)-CH_(2)-CH_(2)-Br`

A

IgtIIgtIII

B

IIIgtIIgtI

C

IIgtIIIgtI

D

IgtIIIgtII

Text Solution

Verified by Experts

The correct Answer is:
D
`underset((I)" "("has 2 "beta-"substituents"))(CH_(3)-underset(CH_(3))underset(|)overset(H)overset(|)(.^(alpha)C)-.^(alpha)CH_(2)Br)" "underset((II)" "("has no "beta-"substituent"))(overset(alpha)(C)H_(3)-overset(alpha)(C)H_(2)-Br) underset((III)" "("has 1 "beta-"substituent"))(CH_(3)-overset(beta)(C)H_(2)-overset(alpha)(C)H_(2)-Br)`
More the number of `beta`-substituents (alkyl groups), more stable alkene it will form on `beta`-elimination and more will be the reactivity. thus, the decreasing order of the rate of `beta`-elimination reaction with alcoholic KOH is:
IgtIIIgtII
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