The critical angle of a certain medium is `sin ^(-1)((3)/(5))`. The polarizing angle of the medium is :

Options

A. `sin^(-1)((4)/(5))`
B. `tan^(-1)((5)/(3))`
C. `tan^(-1)((3)/(4))`
D. `tan^(-1)((4)/(3))`

Answer

B

Explanation

Here, Critical angle, `i_(e) =sin^(-1) ((3)/(5))`
`therefore sin i_(c)= (3)/(5)`
As `mu=(1)/(sin i_(c)) =(5)/(3)`
According to Brewster's law
`tan i_(p)=mu`
where `i_(p) ` is the polarising angle
`therefore tan i_(p) =(5)/(3) rArr i_(p) =tan^(-1) ((5)/(3))`