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A gas mixture contains 50% helium and 50...

A gas mixture contains `50%` helium and `50%` methane by volume. What is the percent by weight of methane in the mixture.

A

`80.0%`

B

`20.05%`

C

`50%`

D

`75%`

Text Solution

Verified by Experts

The correct Answer is:
A

Solution contain `He+CH_(4)`
Their `mol. Wt.=4+16=20`
`% wt.` of `CH_(4)=(wt. of CH_(4))/("Total wt". )xx100=(16)/(20)xx10=80%`
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