[" 22.The velocity of a body of mass "2kg" as a function of tis given by "v'(t)=2t" it "t'" ,"F" ."],[" momentum and the force acting on it,at time "t=2s" ."]

The velocity of a body of mass 2 kg as a function of t is given by v(t) = 2t hati + t^(2)hatj . Find the momentum and the force acting on it, at time t = 2s.

The velocity of a body of mass 2 kg as a function of t is given by vec v (t) = 2t hat i + t^2 hatj . Find the momentum and the force acting on it, at time t = 2s.

The velocity of a body of mass 2 kg as a function of t is given by upsilon(t) = 2t hati + t^(2) hatj Find the momentum and force acting on it at time t = 2 s .

The velocity of a body of mass 2 kg as a function of t is given by upsilon(t) = 2t hati + t^(2) hatj Find the momentum and force acting on it at time t = 2 s .

The velocity of a body of mass 2 kg as a function of t is given by upsilon(t) = 2t hati + t^(2) hatj Find the momentum and force acting on it at time t = 2 s .

The momentum of a body is given by vecP = (10t^2hati + 5thatj) kg-m//s . Find the force acting on the body at t = 2s.

A body of mass 1kg is moving according to the law x(t)=(5t+4t^(2)+6t^(3))m . The force acting on the body at time t=2s is

The position-time graph of a body of mass 2 kg is as given in figure. What is the impulse on the body at t = 0 s and t = 4s.

The displacement of a body of mass 2 kg varies with time t as S = t^(2) + 2t , where S is in seconds. The work done by all the forces acting on the body during the time interval t = 2s to t = 4s is