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If .^(n)C(p)=^(n)C(q)andpneq then n-p=...

If `.^(n)C_(p)=^(n)C_(q)andpneq` then n-p=

A

n-q

B

p

C

q

D

`p+q`

Text Solution

Verified by Experts

The correct Answer is:
C
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