The heat of combustion of butane is `2880kJ" "mol^(-1)`. What is the heat liberated by buring 1 kg of butane in excess of oxygen supply?

Options

A. `498 kJ g^(-1)`
B. `49.8 kJ g^(-1)`
C. `4.98 kJ g^(-1)`
D. `0.498 kJ g^(-1)`

Answer

B

Explanation

Calorific value of butane `C_(4) H_(10)`
`=(Delta H_(c)" of butane")/("Molecular weight")=(2890)/(58)=49.8 kJ//g`