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The radius of the curved road on a natio...

The radius of the curved road on a national highway is `R`. The width of the road is `b`. The outer edge of the road is raised by `h` with respect to the inner edge so that a car with velocity `v` can pass safe over it. The value of `h` is

A

`(v^(2)b)/(Rg)`

B

`(v)/(Rgb)`

C

`(v^(2)R)/(g)`

D

`(v^(2)b)/(R )`

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The correct Answer is:
To find the height \( h \) of the outer edge of the curved road with respect to the inner edge, we can use the principles of circular motion and the geometry of the road. ### Step-by-Step Solution: 1. **Understanding the Geometry:** - The road is curved with a radius \( R \). - The width of the road is \( b \). - The outer edge is raised by a height \( h \) compared to the inner edge. - The angle of the banked road is \( \theta \). 2. **Relating Height and Width:** - The angle \( \theta \) can be expressed using the tangent function: \[ \tan \theta = \frac{h}{b} \] - This means: \[ h = b \tan \theta \] 3. **Forces Acting on the Car:** - When a car is moving on the banked road, it experiences two forces: gravitational force \( mg \) acting downwards and the normal force \( N \) acting perpendicular to the surface of the road. - There is also a centripetal force required for the car to move in a circular path, which is provided by the horizontal component of the normal force. 4. **Setting Up the Equations:** - The components of forces can be resolved as follows: - The vertical component: \[ N \cos \theta = mg \] - The horizontal component (centripetal force): \[ N \sin \theta = \frac{mv^2}{R} \] 5. **Dividing the Equations:** - From the two equations, we can eliminate \( N \): \[ \frac{N \sin \theta}{N \cos \theta} = \frac{\frac{mv^2}{R}}{mg} \] - This simplifies to: \[ \tan \theta = \frac{v^2}{gR} \] 6. **Relating \( h \) and \( b \):** - Substituting the expression for \( \tan \theta \) into the equation for \( h \): \[ \tan \theta = \frac{h}{b} = \frac{v^2}{gR} \] - Therefore, we can express \( h \) in terms of \( b \): \[ h = b \cdot \frac{v^2}{gR} \] 7. **Final Expression for \( h \):** - Thus, the height \( h \) can be calculated as: \[ h = \frac{v^2 b}{gR} \] ### Conclusion: The value of \( h \) is given by: \[ h = \frac{v^2 b}{gR} \]

To find the height \( h \) of the outer edge of the curved road with respect to the inner edge, we can use the principles of circular motion and the geometry of the road. ### Step-by-Step Solution: 1. **Understanding the Geometry:** - The road is curved with a radius \( R \). - The width of the road is \( b \). - The outer edge is raised by a height \( h \) compared to the inner edge. ...
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CP SINGH-CIRCULAR MOTION-Exercise
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