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A particle moves in a circle of radius 2...

A particle moves in a circle of radius 25 cm at two revolutions per sec. The acceleration of the particle in `m//s^(2)` is:

A

`pi ^(2)`

B

`4pi^(2)`

C

`8pi ^(2)`

D

`2pi ^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`a= r omega^(2) = 4 pi ^(2) n^(2) r = 4pi ^(2) xx4xx 0.25 = 4 pi ^(2) `
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