The earth `(mass = 10^(24) kg)` revolves round the Sun with an angular velocity `2 xx 10^(-7) rad s^(-1)` in a circular orbit of radius `1.5 xx 10^(8)km`. Find the force exerted by the Sun on the earth (in `xx 10^(21)N)`.
A
Zero
B
`18xx10^(20)N`
C
`27xx10^(30)N`
D
`3.6xx10^(22)N`
Text Solution
Verified by Experts
The correct Answer is:
D
The gravitational force exerted by the sun on the earth is equal to the C.P force `(mv ^(2) )/(r ) = mr omega^(2)` ` therefore f= mr omega ^(2) = 6xx10^(24) xx1.5 xx10 ^(8) xx10^(3) xx(2xx10^(-7) )^(2)` `=36xx10^(24+8+3-14 )=3.6 xx10^(22) N`
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