Home
Class 12
PHYSICS
The magnetic moment of an electron of ch...

The magnetic moment of an electron of charge e moving in a circular orbit of radius r with speed v is given by

A

qvR

B

`(pi Rqv)/(2(pi+2)`

C

`(qvR)/(3)`

D

`(qvpiR)/(pi+2)`

Text Solution

Verified by Experts

The correct Answer is:
C
M=IA where A=`pir^(2)`
and `I=(dq)/(dt)=(e )/(T)=(e )/(2pir/(T))=(ev)/(2pir)`
`therefore M=(ev)/(2pir)xxpir^(2)=(evr)/(2)`
Promotional Banner

Topper's Solved these Questions

  • MAGNETISM

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|15 Videos

  • MAGNETIC EFFECTS OF ELECTRIC CURRENT

    MARVEL PUBLICATION|Exercise MCQ|195 Videos

  • OSCILLATIONS

    MARVEL PUBLICATION|Exercise MCQ|368 Videos

Similar Questions

Explore conceptually related problems

What is the magnetic moment of an electron orbiting in a circular orbit of radius r with a speed v?

Obtain an expression for the magnetic moment of an electron moving with a speed ‘v’ in a circular orbit of radius ‘r’. How does the magnetic moment change when : (i) the frequency of revolution is doubled? (ii) the orbital radius is halved?

An electron of charge 'e' is revolving in a circular orbit of radius r around a nucleus with speed v. The equivalent current is

An electron moves in circular orbit of radius r with constant speed v.The force acting in it is

The angular momentum of the electron moving around the nucleus in a circular orbit of radius r is given by

If the angular momentum of an electron revolving in a circular orbit is L , then its magnetic moment is

If a charge q is moving in a circle of radius r with speed v, then the equivalent current will be :

An electron of charge e is moving in a circular orbit of radius r around a nucleus, at a frequency v. The magnetic moment associated with the orbital motion of the electron is

In a hydrogen atom, an electron carrying charge 'e' revolves in an orbit of radius 'r' with speed 'v' . Obtain an expression for the magnitude of magnetic moment of a revolving electron.