For the reaction system,
`2NO(g)+O_(2)(g) to 2NO_(2)(g)` volume is suddenly reduced to half its value by increasing the pressure on it. If the reaction is of first order with respect to `O_(2)` and second order with respect to No, the rate of reaction will

Options

A. diminish to one-eighth of its initial value
B. increase to eighth times of its initial value
C. increase to fourth times of its initial value
D. diminish to one-fourth of its initial value

Answer

B

Explanation

`r=k[O_(2)][NO]^(2)`. When the volume is reduced to `(1)/(2)`, the conc. Will double.
`thefore` Newrate`=k[2O_(2)][2NO]^(2)=8k[O^(2)][NO]^(2)`
The new rate increase to eight times of its initial.