[" perpendicular distance from the origin to the plane containing "],[(2)/(5)=(y-2)/(5)=(z+5)/(7)" and "(x-1)/(1)=(y-4)/(4)=(z+4)/(7)" ,is "]

The perpendicular distance from the origin to the plane containing the two lines,(x+2)/(3)=(y-2)/(5)=(z+5)/(7) and (x-1)/(1)=(y-4)/(4)=(z+4)/(7) is: (a) 11sqrt(6)(b)(11)/(sqrt(6))(c)11(d)6sqrt(11)

The perpendicular distance from the origin to the plane containing the two lines, (x+2)/3=(y-2)/5=(z+5)/7 and (x-1)/1=(y-4)/4=(z+4)/7 is: (a) 11sqrt6 (b) 11/(sqrt6) (c) 11 (d) 6sqrt(11)

The perpendicular distance from the origin to the plane containing the two lines, (x +2)/( 3) = ( y -2)/(5) = (z + 5)/(7) and (x-1)/(1) = (y-4)/(4) = (z+4)/(7), is (p)/(sqrtq), then pq is

The plane containing lines (x+1)/(3)=(y+3)/(5)=(z+5)/(7)" and "(x-2)/(1)=(y-4)/(4)=(z-6)/(7) passes through

Find the equation of the plane containing the lines (x-5)/(4)=(y-7)/(4)=(z+3)/(-5) and (x-8)/(7)=(y-4)/(1)=(z-5)/(3)

Find the equation of a plane containing the lines (x-5)/(4)=(y-7)/(4)=(z+3)/(-5) and (x-8)/(7)=(y-4)/(1)=(z-5)/(3)

Find the equation of plane containing the lines (x-5)/(4)=(y+7)/(4)=(z+3)/(-5) and (x-8)/(7)=(y-4)/(1)=(z-5)/(3) .

Find the equation of plane containing the lines (x-5)/(4)=(y+7)/(4)=(z+3)/(-5) and (x-8)/(7)=(y-4)/(1)=(z-5)/(3) .

Find the equation of the plane containing the lines (x-5)/4=(y-7)/4=(z+3)/(-5)a n d(x-8)/7=(y-4)/1=(z-5)/3dot